-18^%

Finding Polarity of an Electromagenet

Available:In Stock

Product SKU: LGSK032

Wishlist

₹ 129 ~~₹ 159~~

Available offers

Best Rates

on Express Shipping – Hurry! Shipping starts from Rs69.

Free Shipping Offer -

Avail free shipping on all orders above Rs999.

Volume Discounts-

Buy More Save More! Discounts upto 20%. Contact us

Special Bulk Discounts

for colleges, Schools, Companies & resellers Contact us

Cash on Delivery

Available above Rs 499

Highlights

Product Code: LGSK032
Technical support - available on email
Handmade
Make in India

Services

Cash on Delivery
Video support to be purchased separately

20% Deposit before shipping On Ready made kit

Easy Payment Options

Netbanking
Debit/Credit cards
Cash on Delivery
E-wallets/UPI

How Fast We Ship

International Shipping

Available

DO IT YOURSELF

READY TO USE

Details

Solderless Paper circuit.
Includes: Circuit drawn on paper and its components, connecting wires
Documentation: Description, Component list, and Circuit diagram.
Power Supply: No battery included, Includes 9 Volt Battery cap only.
Video tutorial is available on YouTube.

One set with its components & wires in running condition.
Documentation: Description, Component list, and Circuit diagram.
Power Supply: No battery included, Includes 9 Volt Battery cap only.
Video tutorial is available on YouTube.

Quantity

Need Volume Discounts? Deals are specially designed for you. Click here

Need help with your idea. Provide us more details Click here

🏠 Warehouse Details:

- -

Specification

Description

This circuit can be used to demonstrate two concepts. One is, how the electric current can induce a magnetic field, and second how the polarity of a DC supply can be reversed by using four switches. If any current flows through any coil made of conductors(generally copper), then a magnetic field will be induced. The direction can be checked by using a metal or a piece of magnet. If the direction of the current is reversed, then the direction of the induced field will also be reversed. In the given circuit let us suppose we have open switches S2,S4 and closed switches S1, and S3. Clearly, the current will flow from V2 to V3. Now if we open S1, and S3 and close S2, and S4, clearly the current will flow from V3 to V2.